The Batman Equation

Discussion in 'HardForum Tech News' started by HardOCP News, Jul 29, 2011.

  1. HardOCP News

    HardOCP News [H] News

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    The Batman equation, what the hell is the Batm... whoa, wait....what? Blame Ryan North for this one.
     
  2. TheGamerZ

    TheGamerZ [H]ardness Supreme

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  3. DyNamiC.

    DyNamiC. [H]ard|Gawd

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    Nerd.


    That is all.

    :p
     
  4. zaxour

    zaxour [H]ard|Gawd

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    I (r=1-sin(theta)) this equation.
     
  5. faugusztin

    faugusztin 2[H]4U

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    Someone has too much spare time (or is very bored).
     
  6. weebling1

    weebling1 2[H]4U

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    just don't try to prove mathmaticly that you don't exist ffs :p
     
  7. BladeVenom

    BladeVenom [H]ardness Supreme

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    So who's double checked it?
     
  8. xorbe

    xorbe [H]ardness Supreme

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    Can any one check this with Batlab or Batmatica?
     
  9. Trimlock

    Trimlock [H]ardForum Junkie

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    In 1.4 increments too, was this person going for average size or something or does this person just hate life?
     
  10. HRslammR

    HRslammR 2[H]4U

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    Faster TI-83 FASTER!
     
  11. okashira

    okashira [H]ard|Gawd

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    No need. The graph is clearly piece-wise, but the equation is not. It's faked.
     
  12. MavericK

    MavericK Zero Cool

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    Yeah, that's what I was thinking. Sad because it looked epic.
     
  13. LuminaryJanitor

    LuminaryJanitor 2[H]4U

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    |x| is a piecewise function, and the equation contains 19 of them...
     
  14. SCSI-Terminator

    SCSI-Terminator Gawd

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    I dunno, there's alot of absolute signs in there, which can yeild some hard corners.
     
  15. Shalafi

    Shalafi Consigliere

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    In the Dark Knight Rises, Batman will add the TI-83 calculator to his arsenal.

    He'll whip that thing out and chuck it at the bad guy, it has serrated blades on both ends of it.

    Damn, who knew mathematics could be so deadly?
     
  16. sfsuphysics

    sfsuphysics I don't get it

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    Its been a long time since I took a math class, but that fails the vertical line test so it is not a function! So the batsignal won't do anything :D
     
  17. xorbe

    xorbe [H]ardness Supreme

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    Well it's not a function with a 1:1 mapping of x/y values ... but it is a valid equation ...
     
  18. okashira

    okashira [H]ard|Gawd

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    You are right, it may have some merit. ill check i tomorrow if I get bored
     
  19. okashira

    okashira [H]ard|Gawd

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    Thing is, it goes from first order quadratic (in x and y) to higher order in a discontinous fashion at what looks like x=.707 (on purpose I suppose) and I don't think you can just do that with a combination of absolute signs...
     
  20. okashira

    okashira [H]ard|Gawd

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    and I was just about to correct my self and say at x=1 but instead I realized there is a way to change the "order" of the equation using a combination of abs signs in fraction form. It's probably real. :p
     
  21. AthlonXP

    AthlonXP [H]ard as it Gets

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    As long as it does not involve Christian Bale I am fine with that...
     
  22. Sly

    Sly [H]ardness Supreme

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    I don't suppose you can borrow a college classroom and explain that equation on youtube?
     
  23. vengence

    vengence Level capped

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    the fact it's not piece wise if impressive.
     
  24. FndTheRver

    FndTheRver Gawd

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    That's fantastic! I was impressed.
     
  25. thedigeffect

    thedigeffect n00b

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    I tried to plot it, but all I get is a blank plot in Mathematica. Maybe I made a typo in translating it, or maybe it's too much for it.

    Code:
    ContourPlot[
     
     ((x/7)^2*Sqrt[Abs[Abs[x] - 3]/(Abs[x] - 3)] + (y/3)^2*Sqrt[
          Abs[y + (3 Sqrt[33])/7]/(y + (3 Sqrt[33])/7)] - 
         1)*(Abs[x/2] - ((3 Sqrt[33] - 7)/112) x^2 - 3 + Sqrt[
         1 - (Abs[Abs[x] - 2] - 1)^2] - 
         y)*(9 Sqrt[
          Abs[(Abs[x] - 1) (Abs[x] - .75)]/((1 - 
             Abs[x]) (Abs[x] - .75))] - 8*Abs[x] - 
         y)*(3*Abs[x] + .75 Sqrt[
          Abs[(Abs[x] - .75) (Abs[x] - .5)]/((.75 - 
             Abs[x]) (Abs[x] - .5))] - 
         y)*(2.25 Sqrt[Abs[(x - .5) (x + .5)]/((.5 - x) (.5 + x))] - y)*((
         6 Sqrt[10])/
         7 + (1.5 - .5*Abs[x]) Sqrt[Abs[Abs[x] - 1]/(Abs[x] - 1)] - (
          6 Sqrt[10])/14 Sqrt[4 - (Abs[x] - 1)^2] - y) == 0
     
     , {x, -10, 10}, {y, -10, 10}]
     
  26. 753951

    753951 n00b

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    Coworker and I tried it in Mathematica 7 and 8 with same result (blank plot). Then we dumped results into table and ended up with bunch of imaginary numbers. Looks like fake.
     
  27. Methadras

    Methadras [H]ardness Supreme

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    Total fake, but still funny.
     
  28. Trimlock

    Trimlock [H]ardForum Junkie

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    :p
    Yea I tried the same and got the same results. Interesting but its fake imp.
     
  29. HRslammR

    HRslammR 2[H]4U

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    This.