http://www.tricklife.com/view.php?id=759
That is awesome....but it looks unreal....anybody know more about this?
That is awesome....but it looks unreal....anybody know more about this?
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Put fish in it!![]()
I've seen someone on here do it a while back. Its pretty cool. I have some old hardware laying around, so maybe I'll try it sometime. Cool video though.![]()
It's a horrible idea! What happens when the oil gets hot? The system gets hot, then what?? It overheats. Then you are fuc*** because you wasted money on the oil, and now you have to clean everything.
You'd need a radiator and high-flow pump to make it worthwhile -- pulling the oil out at the top, returning the cooler stuff at the bottom.
I read the original article by Puget Systems and they said that it worked fine for a while, temps started low, but eventually they got higher that just running on air because the ambient temp of the oil went up and the heat was trapped in it. They added the bubbler trying to add more turbulence, hoping it would get the heat out of the oil, but it wasn't much help.
You dump some french fries in.What happens when the oil gets hot?
7 gallons at $60.00 a gallon = $420.00 just for the oil. Seems you could buy a very nice watercooling setup for that price.![]()
7 gallons at $60.00 a gallon = $420.00 just for the oil. Seems you could buy a very nice watercooling setup for that price.![]()
Thank you.
And to Jay_oasis. Its going to get hot, I would give it an hour. And no OC'ing with this type of cooling.
Thank you.
And to Jay_oasis. Its going to get hot, I would give it an hour. And no OC'ing with this type of cooling.
Read above! Its going to overheat, your going to burn something up. If nothing burns up well.... The computer will be restarting allot. Nice thing to try if you are bored oen weekend and have money to waste on pointless oil.
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It is 7.30 lb/gal so your 6 gallons would be 43.8 lbs...converting to metric that comes out to be 19.9 kg of mineral oil.
Specific heat is 2023 J/(kg-°K) at 80C...now 1 watt-hour = 3600 J
So you need 2023 J/(kg-°K) x 19.9 kg = 40,258 Joules to raise the mineral oil one degree Celsius.
At 275W heat input, you are pumping out 275*3600 = 990,000 Joules per hour. So in one hour, assuming the mineral oil tank is vacuum insulated from the environment and is losing zero heat to its surroundings, the mineral oil heats up approximately 990000/40258 = 24.6°C
Your budget is 90°C - 21.1°C = 68.9°C...
68.9/24.6 = 2.8 hours.
In 2.8 hours the 6 gallons of mineral oil will have absorbed enough heat to rise from 21.1C to 90C. Whether it gets there or not depends on how much heat is lost thru the surface area of the tank's sidewalls and the environment."
There you go.
LOOOOOOOOOOL!!!!You dump some french fries in.
$60 was the total cost. It is under $10/gal at your local store such as Meijer.
this isn't really all that new.
A guy on this very board too did something even [h]ardercore. throw a meager rig in a pan, fill it with oil, threw it on a burner, and cooked some fries while running some quake.
Oooo - can you give me a linky please, if there are pics that is.
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It is 7.30 lb/gal so your 6 gallons would be 43.8 lbs...converting to metric that comes out to be 19.9 kg of mineral oil.
Specific heat is 2023 J/(kg-°K) at 80C...now 1 watt-hour = 3600 J
So you need 2023 J/(kg-°K) x 19.9 kg = 40,258 Joules to raise the mineral oil one degree Celsius.
At 275W heat input, you are pumping out 275*3600 = 990,000 Joules per hour. So in one hour, assuming the mineral oil tank is vacuum insulated from the environment and is losing zero heat to its surroundings, the mineral oil heats up approximately 990000/40258 = 24.6°C
Your budget is 90°C - 21.1°C = 68.9°C...
68.9/24.6 = 2.8 hours.
In 2.8 hours the 6 gallons of mineral oil will have absorbed enough heat to rise from 21.1C to 90C. Whether it gets there or not depends on how much heat is lost thru the surface area of the tank's sidewalls and the environment."
There you go.