Stupid C error

[Sayth]

I have a program that reads a file, then writes thhe contents to another file, but I keep getting this stupid ÿ thing at the end of the output file. Any ideas?
Here's my code

#include <stdio.h>
int main()
{
char ifilename[] = "i:/emplistin.txt";
char ofilename[] = "i:/emplistout.txt";
char name;
char ch;
FILE *ofp, *ifp;

{
/* Open file for input */
ifp = fopen(ifilename,"r");

/* Open file for output */
ofp = fopen(ofilename,"w");

while (ch != EOF)


{
/* Read data */
ch = fgetc(ifp);

/* Write out data */
fputc(ch, ofp);

}

/* Close Files */
fclose(ifp);
fclose(ofp);
}

printf("hit enter to end program");
getchar(ch);

return 0;
}

 

[Lord of Shadows]

You are printing out EOF to your output file.

-btw why the random bracket block in the middle of your code?

 

[Sayth]

yeah don't know why that was there... thanks for pointing it out

OKay so how do I not print the EOF? I have to stop the reading at the EOF somehow and the only place I see it in my code is where I want the loop to stop.

 

[Lord of Shadows]

I cant just *tell* you with the homework policy etc, best advice I can give you would be to open your book and look over looping constructs and flow control.

 

[Sayth]

ah yeah I see.. hardforums has become so tightass it's not funny... I remember the good old days... General discussion was the best. Ah well thanx anyways.

 

[eloj]

Hint: "int fgetc(FILE *stream);"

Might also want to think over what happens with an empty file. That'd solve your control-flow problem.

 

[Sayth]

okay thanx guys I fixed my problem, but come accross another...
Is it possible to make the 3 in this line a variable?

fputc(ch+3, ofp);

 

[mikeblas]

Is it possible to make the 3 in this line a variable?

Yes.

 

[Sayth]

hah sweet I got it after many many attempts
thanx!