Overclocking. Is it worth it?

[Raghar]

Explain that to me.

Same Vcc yet >MHz = more power. Huh?
That's the dumbest thing I've heard in my life.

One clock, one pulse where CPU is doing work. (aka one picoJoule of work or so) More pulses per second, more watts are going through CPU.

 

[LigTasm]

Explain that to me.

Same Vcc yet >MHz = more power. Huh?
That's the dumbest thing I've heard in my life.

Please tell me how in the hell an overclocked system on stock voltage across the board takes up more power than a completely 100% stock system.
Maybe you're putting too much emphasis into 'auto' typically overvolting, and I can agree with that. But when you actually dial in the exact voltage required under stock and all you do is raise the BCLK or the multiplier - you are using no more power than a stock system. Less, in fact, because you're no longer running on 'auto' and dealing with overvoltage.

Voltage =/= current. Frequency increase means more current draw. More current draw means more Wattage (a unit of power). Watts = V x A. Some simple understanding of electrical theory would help your argument hold water, but unfortunately you're shooting from the hip.

 

[zero2dash]

^^^ Yeah, I'm no electrician.
Those two posts explain it a lot better.

 

[Raghar]

I thought even child can understand my explanation. It was really simple, I even didn't need to use words like power gating...

 

[RamonGTP]

Explain that to me.

Same Vcc yet >MHz = more power. Huh?
That's the dumbest thing I've heard in my life.

Please tell me how in the hell an overclocked system on stock voltage across the board takes up more power than a completely 100% stock system.
Maybe you're putting too much emphasis into 'auto' typically overvolting, and I can agree with that. But when you actually dial in the exact voltage required under stock and all you do is raise the BCLK or the multiplier - you are using no more power than a stock system. Less, in fact, because you're no longer running on 'auto' and dealing with overvoltage.

By this logic, a blow dryer with the heating element turned off would consume the same amount of power as it does with the heating element turned on since either way it has the same voltage going into it.

As has been mentioned before, voltage is only one factor of power consumption, the other is current (amps). Multiply those together and you get your total power draw (in watts)

 

[DejaWiz]

so you actually think that power usage does not go up unless the voltage is increased?

Cannondale is correct.


From Intel:

An increase in processor operating frequency not only increases system performance, but also increases the processor power dissipation. The relationship between frequency and power is generalized in the following equation:

P = CV2F

(where P = power, C = capacitance, V = voltage, F = frequency).
From this equation, it is evident that power increases linearly with frequency and with the square of voltage.

Let's try a bit of math:
i5-3570K STOCK
P = 77W
V = 1.2V
C = ???

Using the formula, find C.
C=P/F/V^2
C=77/3400/1.2^2
C=0.01573

Just to verify our math:
P = C * V^2 * F
P = 0.01573 * 1.44 * 3400
P = 77W

Now, let's OC it to 4.4GHz, but using the same 1.2Vcore

P = C * V^2 * F
P = 0.01573 * 1.44 * 4400
P = 99.67W

Hmmm, almost a 30% increase in power use and no voltage increase in sight.

 

[Syphon Filter]

Sorry for not checking back sooner.

I'm glad that someone explained the situation re power usage when OCing to zero2dash.