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I'm just starting out with PHP and I've got a very basic test right now...
I've got two HTML forms defined in the following page, this page also displays the current data contained in the table:
When this form is submitted it calls the following page:
What I'm seeing is that only the first value (inserted through $sql) is being written to the database.
Any ideas why?
I've got two HTML forms defined in the following page, this page also displays the current data contained in the table:
Code:
<?
include 'main/security.php';
//connect
$db = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db("$dbname",$db);
$sql = "SELECT * FROM test";
$result = mysql_query($sql);
$fields_num = mysql_num_fields($result);
echo "<h1>Testing Results: {$table}</h1>";
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
?>
<html>
<body>
<form action="insert.php" method="post">
text: <input type="text" name="text" />
info: <input type="text" name="info" />
<input type="submit" />
</form>
</body>
</html>When this form is submitted it calls the following page:
Code:
<?php
include 'main/security.php';
$db = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db("$dbname",$db);
$sql="INSERT INTO test (text)
VALUES
('$_POST[text]')";
$test="INSERT INTO test (info)
VALUES
('$_POST[info]')";
if (!mysql_query($sql,$db))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($db)
?>
<html>
<a href="test.php">Click here to go back to the main page</a>
</html>What I'm seeing is that only the first value (inserted through $sql) is being written to the database.
Any ideas why?