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Loop Size?

cheesehazard

Weaksauce
Joined
Dec 15, 2005
Messages
97
What is better, a smaller loop or a larger loop? I am trying to get an idea on how to build my new water cooled system.
 
Define small and large loop.

What are you cooling?

How much space do you have in your case or are you doing an external mount?
 
I am cooling my cpu right now but depending on the temps I get after I put the system together I maybe cooling my video card as well. I have a drive bay reservoir that I am debating on using. Right now I have the tubes as short as possible with no reservoir and only 1 valve to bleed the system as anything extra. I am trying to find out if the reservoir will increase my temps or lower them. I am using 3 40x40 peltiers as my "radiator". I was getting temps that stayed around 19C for a while but as of late my temps are getting higher and higher.
 
In general, more water (more reservoirs) in the system means lower temperatures. This is due to the fact that it takes longer to bring a larger body of water to an equivalent temperature. However, some systems are so small (little distance between successive components) that this makes little difference.

Now, once that body of water is at an equivalent temperature, your cooling efficiency flattens out. I'm speaking like I'm looking at a graph right now so if that doesn't make sense let me know....

-EGA Wrangler
Chemist, Computer Scientist, and Captain of Marines
 
more water (more reservoirs) in the system means lower temperatures.

Wouldn't a higher water capacity simply mean a larger /\T between the base coolant temperature, and the temperature of load equilibrium?

I mean, if you want to get technical with it :p
 
In general, more water (more reservoirs) in the system means lower temperatures. This is due to the fact that it takes longer to bring a larger body of water to an equivalent temperature. However, some systems are so small (little distance between successive components) that this makes little difference.

Now, once that body of water is at an equivalent temperature, your cooling efficiency flattens out. I'm speaking like I'm looking at a graph right now so if that doesn't make sense let me know....

Well if your talking about using a bathtub for a reservoir you would be correct until you reach a temp equilibrium. However, almost all water cooling systems I have ever seen it wouldn't make for much more than a few minutes at most.

So the answer should be, in amateur water cooling, that it just plain doesn't really matter. :)
 
Wouldn't a higher water capacity simply mean a larger /\T between the base coolant temperature, and the temperature of load equilibrium?

I definitely see the 'technical' words there, but I'm not sure I can follow your thought process. :) In fluid dynamics, load equilibrium is the aggregate pressure caused by an induced device (or group thereof). Ignoring atmospheric pressure, this comes from pumps, valves, reducers, etc. Regardless, Snoozer said it WAY better than I did.

Well if your talking about using a bathtub for a reservoir you would be correct until you reach a temp equilibrium. However, almost all water cooling systems I have ever seen it wouldn't make for much more than a few minutes at most.

Spot on. I think that's exactly what I said, but just in way better terms since I kind of butchered it. BTW, I've seen several large systems at SPAWAR that use anywhere from 30-50 gallon tanks. Their 'warm up' time is about six hours.

-EGA Wrangler
Chemist, Computer Scientist, and Captain of Marines
 
I definitely see the 'technical' words there, but I'm not sure I can follow your thought process. In fluid dynamics, load equilibrium is the aggregate pressure caused by an induced device (or group thereof). Ignoring atmospheric pressure, this comes from pumps, valves, reducers, etc. Regardless, Snoozer said it WAY better than I did.

I had no idea "load equilibrium" was an actual term, rather than something I had come up with to describe the equilibrium coolant temperature reached with a specific heat load.

Neat, I learned something.
 
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