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easy one that I got wrong
Question: What valid host range is the IP address 192.168.254.100 255.255.255.192 a part of?
256-192=64
2^6=64 32-6=26 /26 is your subnet (Showed that so you can see how I figure those out.)
64 is your range in the last octet.
x.x.x.0-x.x.x.63
x.x.x..64-x.x.x.127
x.x.x.128-x.x.x.191
x.x.x.192-x.x.x.255
You can't use the first and last IPs in a range so the range would be:
192.168.254.65 - 192.168.254.126
? I gave you the answer. It's 192.168.254.65 - 192.168.254.126.