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Recent content by surazal

  1. S

    Some PHP Syntax help

    if ($row[password] == '$password') This line is wrong, I'm surprised it didn't throw an error. Indexes to associative arrays are strings so it needs quotes. Using single quotes around $password will evaluate the right side to the string $password and not what $password is equal to. Use...
  2. S

    Some PHP Syntax help

    I just noticed an even more glaring error if ($user = $row['username'] AND $pass = $row['password']) I assume you meant to use == for comparison and not = for assignment. Using === for typed comparison would be even better. Your current code will return true for any username and pass.
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    Some PHP Syntax help

    In mysql, all strings should be enclosed in single or double quotes. Username and password in the code above are strings, so they must have quotes around them. In php, single quotes doesn't evaluate any variables. Double quotes will parse and evaluate variables in the string. I've read...
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    IE CSS Problem

    add this #tags li { display: inline; }
  5. S

    using php and an array to display thumbs

    if you already have an array of filenames, why not just do this foreach($images as $img) { echo "<img src=\"$img\">"; }
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    X3350 or Q9450, which OC's better?

    Same situation for me. Guess everyone is using their hookups to get this CPU :D Anyone know when supply is expected?
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    PHP debugging issue

    You are inserting the strings 'prod_name', 'qty', and 'item_desc' instead of what is contained in those variables. It should be '$prod_name', '$qty', '$item_desc'. Like I said before, if a query isn't working the way you think it does or if it is throwing an error, print out the query string...
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    PHP debugging issue

    There are a few things wrong with that query. I'm assuming the $prod_name is a string which needs to be wrapped in single quotes. There is also an extra single quote after $item desc. When I said echo the query string, I meant echo what you were passing into the mysql_query function. For...
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    PHP debugging issue

    Print or echo the whole query. It is the best way to debug them.
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    mySql logical operators not working

    It's probably better to keep the sql statement in a variable for 2 reasons. It's easier to print out the statements when you are debugging and you'll have to start doing it when you build more complex queries ie. adding or removing conditionals based on how the user inputs data. Your time...
  11. S

    Having problem with php include conflict

    Don't include directly from a GET variable, that's a big security risk. A safer method is to have the GET variable hold a name of the page you want to load, then use a switch statement or a series of if statements to load the correct filename. for example: switch( $_GET["id"] ) { case...
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    Quick PHP problem regarding drop down box with default "selected"

    No, == and === are two different comparison operators. http://us3.php.net/operators.comparison 0 == '0' will evaluate to true 0 === '0' will evaluate to false
  13. S

    Same browser version, same page, different display

    Are the other text on that computer enlarged as well? The DPI settings might have been changed if they are. Check under Display Properties -> Settings -> click advanced -> General.
  14. S

    Quick PHP problem regarding drop down box with default "selected"

    PHP doesnt use + for string concatenations anywhere, it is always the . syntax. The reason that the conditional was always evaluating to true in your original code is because ($firstname + " " + $lastname) evaluates to integer 0. The interpreter makes a best guess and typecasts $firstname...
  15. S

    CSS/Javascript/Html Help

    One possible solution is to take in the name of the link as a paramter to the function <script type="text/javascript"> var links = new Array("home", "login", "register", "booklist", "deletebook", "displaybooks"); function showlink(linkname) { //set all to hidden first for (var...
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