I'm gonna give the following statements and you tell me whether I'm right or wrong please: The number of ampers indicate only the potential of a transformer. Meaning: if I connect only a low power consumer to a high power PSU / transformer set, it will consume only the power at the consumer's rate and not more. If the PSU has only low power consumers connected, it draws less current from the transformer. The PSU as well as the transformer stay well under the full load limit, and every component works fine and stays cool or warm. If the PSU has to power 3 HDDs, a DVD-R, a quad CPU and a discrete high end graphics card, it demands as much current as it needs from the transformer / or as much current as the transformer can deliver. >>> If the transformer cannot deliver the current requested, it runs at 100% which lets the components run just about, if at all ... and the transformer gets very hot and can get damaged. >>> If the transformer can deliver the full requested capacity of the PSU (i.e. 8A), then the components and the transformer run fine, but the PSU runs at 100% and gets too hot and can get damaged. Is that about right, what I think how it works ? If yes, then an overpowered transformer (i.e. 12.5A) cannot damage an underpowered PSU (i.e. 8A), as long as the voltage matches (i.e. 12V), because the PSU is not able to draw more than the maximum number of ampers it can handle anyway (i.e. 8A). Or am I thinking wrong and the PSU, which is layed out to handle up to 8A, can in fact be damaged by connecting consumers drawing 8A or more ... which makes the PSU draw more current from an overpowered transformer ... following a damage of the PSU. Can you confirm or dispute ? Thanks PS: the reason why I started this thread, is that I have chosen >>> this <<< PSU and >>> this <<< transformer. As you can see, the PSU can handle up to 8A while the transformer can handle up to 12.5A I am now confused whether the overpowered transformer can damage the PSU und the connected consumers.