Start your math test prep now with our free ACT Math Practice Tests. Topics covered include pre-algebra, elementary algebra, intermediate algebra, coordinate geometry, plane geometry, and trigonometry.

*Difficulty Level – 1:* *Easy*

**Directions:** Solve each problem and then click on the correct answer. You are permitted to use a calculator on this test.

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Question 1 |

### If $4x + 3x − 2(x + 5) = −9$, then $x = \; ?$

$−\dfrac{1}{2}$ | |

$0$ | |

$\dfrac{1}{5}$ | |

$\dfrac{2}{3}$ | |

$\dfrac{4}{5}$ |

Question 1 Explanation:

The correct answer is (C). Evaluate the expression by first distributing the −2 through the parentheses:

$7x − 2x − 10 = −9$

$5x = 1$

$x = \dfrac{1}{5}$

$7x − 2x − 10 = −9$

$5x = 1$

$x = \dfrac{1}{5}$

Question 2 |

### If the ratio of milk cartons to juice boxes is 13:$x$ and there are 39 milk cartons and 18 juice boxes, what is the value of $x$?

$4$ | |

$6$ | |

$8$ | |

$10$ | |

$12$ |

Question 2 Explanation:

The correct answer is (B). Solve this problem by setting up a proportion. We are told the ratio of milk to juice is 13:$x$ and that there are 39 milk and 18 juice:

$\dfrac{13}{x} = \dfrac{39}{18}$

Cross multiply and solve for $x$ to get 6.

$\dfrac{13}{x} = \dfrac{39}{18}$

Cross multiply and solve for $x$ to get 6.

Question 3 |

### A triangle, RST, is reflected across the y-axis to form the triangle R′S′T′ in the standard $(x,y)$ coordinate plane; thus, R reflects to R′. The coordinates of point T are $(j,k)$. What are the coordinates of point T′?

$(−j, k)$ | |

$(j, −k)$ | |

$(−j, −k)$ | |

$(k, j)$ | |

$\text{It}$ $\text{cannot}$ $\text{be}$ $\text{determined.}$ |

Question 3 Explanation:

The correct answer is (A). When you reflect a point across the y-axis, the value of its x-value is made negative:

$(j,k) → (−j,k)$

To visualize draw a picture:

$(j,k) → (−j,k)$

To visualize draw a picture:

Question 4 |

### How many of the numbers between 20 and 40 are prime numbers?

$3$ | |

$4$ | |

$5$ | |

$6$ | |

$7$ |

Question 4 Explanation:

The correct answer is (B). A prime number is a number with no factors other than 1 and itself. Therefore, we can solve this problem by listing the numbers from 20 to 40 and eliminating those which are clearly divisible by some other number.

We only really need to list the odd numbers in this range, since the even numbers are obviously divisible by 2 and therefore not prime. 21, 23, 25, 27, 29, 31, 33, 35, 37, 39

Numbers divisible by 3: 21, 27, 33, 39

Numbers divisible by 5: 25, 35

The remaining numbers are 23, 29, 31, and 37. A quick check will tell us that none of these numbers are divisible by anything other than themselves and 1.

Therefore, 4 of the numbers between 20 and 40 are prime (Choice B).

We only really need to list the odd numbers in this range, since the even numbers are obviously divisible by 2 and therefore not prime. 21, 23, 25, 27, 29, 31, 33, 35, 37, 39

Numbers divisible by 3: 21, 27, 33, 39

Numbers divisible by 5: 25, 35

The remaining numbers are 23, 29, 31, and 37. A quick check will tell us that none of these numbers are divisible by anything other than themselves and 1.

Therefore, 4 of the numbers between 20 and 40 are prime (Choice B).

Question 5 |

### If $\, a = −1$ and $\, b = 4$, what is the difference between $\, a^3b +3b$ and $\, a^3b + 3b^0$?

$−11$ | |

$−3$ | |

$2$ | |

$4$ | |

$9$ |

Question 5 Explanation:

The correct answer is (E). Here we are required to initially substitute the known values of $a$ and $b$ into the expressions provided before finding the difference. Substituting the values of $a$ and $b$ into the first expression gives:

$(−1^3)(4) + 3(4)$

$= −4 + 12$

$= 8$

Substituting the values of $a$ and $b$ into the second expression gives:

$(−1^3)(4) + 3(4)^0$

$= −4 + 3(1)$

$= −4 + 3$

$= −1$

The difference between the two expressions is: $8 − (−1) = 9$

Recall that any number (other than 0) to the 0 power is 1 and that subtracting a negative is the same as adding.

$(−1^3)(4) + 3(4)$

$= −4 + 12$

$= 8$

Substituting the values of $a$ and $b$ into the second expression gives:

$(−1^3)(4) + 3(4)^0$

$= −4 + 3(1)$

$= −4 + 3$

$= −1$

The difference between the two expressions is: $8 − (−1) = 9$

Recall that any number (other than 0) to the 0 power is 1 and that subtracting a negative is the same as adding.

Question 6 |

### What is the least common multiple (LCM) of 3, 8, and 10?

$40$ | |

$80$ | |

$120$ | |

$140$ | |

$240$ |

Question 6 Explanation:

The correct answer is (C). The least common multiple of a set of numbers is the smallest number that every number in the set can evenly divide into. To find the least common multiple, begin by performing a prime factorization of the set of numbers, seen here as: 3: 1 * 3; 8: 2 * 2 * 2; 10: 5 * 2. Express these factorizations in terms of the highest power of each factor, seen here as: 3

^{1}, 2^{3}, 5^{1}. We do not include 2^{1}from the factors of 10 because 2^{3}from the prime factorization of 8 is of a higher degree. We now multiply these highest power factors together to find the least common multiple: 3 * 2^{3}* 5 = 120.Question 7 |

### The chart above shows the monthly profits of 3 stores. What is the total profit generated by Store X and Store Z in the month of March?

$20{,}000$ | |

$80{,}000$ | |

$140{,}000$ | |

$180{,}000$ | |

$200{,}000$ |

Question 7 Explanation:

The correct answer is (D). From the chart we can see that Store X had 80 (thousand) in profits and Store Z had 100 (thousand) in profits. Combining these two, we arrive at 180 (thousand) in profits.

Question 8 |

### The chart provided shows the monthly profits of 3 stores. What was the percent increase in Store Y’s profits over the course of the 4 months?

$25\%$ | |

$33\%$ | |

$50\%$ | |

$75\%$ | |

$100\%$ |

Question 8 Explanation:

The correct answer is (E). To calculate percent increase, we subtract the original amount from the new amount and divide the total by the original amount. From the chart we can see that Store Y profited 30 (thousand) in January and 60 (thousand) in April:

$(60 − 30) ÷ 30 = 1.00$

$= 100\%$

$(60 − 30) ÷ 30 = 1.00$

$= 100\%$

Question 9 |

### In order for the two triangles shown to be similar, what is one possible value for $x$?

$8$ $\text{in.}$ | |

$10$ $\text{in.}$ | |

$16$ $\text{in.}$ | |

$20$ $\text{in.}$ | |

$24$ $\text{in.}$ |

Question 9 Explanation:

The correct answer is (C). Problems involving similar figures can be solved using proportions. The issue with this problem is that we are given a similarity across inches to feet with the answer choices containing only inches. First we must convert the feet measurement into inches:

$2\dfrac{1}{3}\text{ft}*\dfrac{12 \text{ in}}{\text{ft}}=28 \text{ in.}$

We can now set up our proportion:

$\dfrac{4}{7}=\dfrac{x}{28} \to x=16 \text{ in.}$

$2\dfrac{1}{3}\text{ft}*\dfrac{12 \text{ in}}{\text{ft}}=28 \text{ in.}$

We can now set up our proportion:

$\dfrac{4}{7}=\dfrac{x}{28} \to x=16 \text{ in.}$

Question 10 |

### In quadrilateral *WXYZ*, what is the degree measurement of $x$?

$60^°$ | |

$75^°$ | |

$80^°$ | |

$90^°$ | |

$120^°$ |

Question 10 Explanation:

The correct answer is (A). The sum of the interior angles of a quadrilateral is 360°:

$84 + 96 + 3x = 360$

$3x = 180$

$x = 60$

$84 + 96 + 3x = 360$

$3x = 180$

$x = 60$

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