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If Beth has more money than Ari, and each person has an inte
[#permalink]
Updated on: 25 Mar 2020, 14:54

Expert Reply

3

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Question Stats:

If Beth has \(\frac{1}{4}\) MORE money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari's money?

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

_________________

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

_________________

Sandy

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Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
19 Aug 2018, 06:58

2

sandy wrote:

If Beth has more money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari’s money?

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

I think something else is required to ans the question. As it is it can be any combination for getting the four options. such as 1+11, 1+53, 2+70, 99 + 101

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:39

Any updates on this? No way the answer is correct per the question.

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:51

Expert Reply

let me find out it, if something is wrong.

Back soon

_________________

Back soon

_________________

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Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:55

Expert Reply

\(B=A+(\frac{A}{4})\)

\(B=\frac{5A}{4}\)

\(\frac{A}{B}=\frac{5n}{4n}\)

The TOTAL amount of money must be a multiple of \(9n (5n+4n)\). So 54 and 72 work.

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\(B=\frac{5A}{4}\)

\(\frac{A}{B}=\frac{5n}{4n}\)

The TOTAL amount of money must be a multiple of \(9n (5n+4n)\). So 54 and 72 work.

_________________

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Questions' Banks and Collection:

ETS: ETS Free PowerPrep 1 & 2 All 320 Questions Explanation. | ETS All Official Guides

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Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:56

Expert Reply

Done

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Questions' Banks and Collection:

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3rd Party Resource's: All Quant Questions Collection | All Verbal Questions Collection

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Vocab: GRE Prep Club Official Vocabulary Lists for the GRE (2021)

_________________

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3rd Party Resource's: All Quant Questions Collection | All Verbal Questions Collection

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How is the GRE Score Calculated -The Definitive Guide (2021)

Tests: GRE Prep Club Tests | FREE GRE Practice Tests [Collection] - New Edition (2021)

Vocab: GRE Prep Club Official Vocabulary Lists for the GRE (2021)

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
17 Oct 2020, 17:28

2

B = (5/4 )* A

A+B = A + (5/4) * A = (9/4)* A , now put the values, the answer is 54 and 72 only

A+B = A + (5/4) * A = (9/4)* A , now put the values, the answer is 54 and 72 only

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
20 Dec 2020, 02:53

May someone help me find out what is my mistake ?

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
16 Jan 2021, 19:48

2

1

Bookmarks

If Beth has 1/4 MORE money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari's money?

the question is asking about combined value of the 2 people, Total = B+A ==>(1)

B alone = A+1/4A ==> B= 5/4A==>(2)

Substitute b with the first equation ==> Total= 5/4A+A==> Total = 9/4A

the only answers is 54 and 72

the question is asking about combined value of the 2 people, Total = B+A ==>(1)

B alone = A+1/4A ==> B= 5/4A==>(2)

Substitute b with the first equation ==> Total= 5/4A+A==> Total = 9/4A

the only answers is 54 and 72

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
16 Jan 2021, 21:30

1

Asmakan wrote:

May someone help me find out what is my mistake ?

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

The correct ans is B and C. Both 54 and 72 when divided by 2.25 gives an integer value.

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos

If Beth has more money than Ari, and each person has an inte
[#permalink]
09 Sep 2021, 20:56

B = A + A/4 = 5A/4

A + B = A + 5A/4 = 9A/4

Total = 9A/4 = 9/4 * A

The least possible value of A is 4 to make the total value an integer.

So, Total = 9/4 * 4 = 9. The answer will be 9 or the multiples of 9.

Ans: B, C

A + B = A + 5A/4 = 9A/4

Total = 9A/4 = 9/4 * A

The least possible value of A is 4 to make the total value an integer.

So, Total = 9/4 * 4 = 9. The answer will be 9 or the multiples of 9.

Ans: B, C

gmatclubot

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