Sure. Just like I sold one last year for $1200 ;)
If you think it's expensive and you want to wait that is fine with me.
This phone with no contract is 699 plus tax. But is only sold to current att customers. People without ATT cannot get it without signing a contract.
and thanks for all...
I hope this wasn't too big of a mistake.
I had Windows Vista 64bit and everything was going fine. Today I bought Protools 8 and when I got home I came to find out that it does not run on Vista 64.
So I decided to install XP pro, I installed on a whole different hard drive but now the computer...
I have a Evga 8800gts that I no longer need.
$80.00 shipped.
Here's the link to it on newegg: http://www.newegg.com/Product/Product.aspx?Item=N82E16814130082
Ebay feedback: phldbr ; 296 points 100% positive.
I just got a new motherboard for my pc. I had a P6N SLI Platinum and switched over to asus p5q deluxe.
Everything went smoothly except that when the hard drive boots into vista it does not recognize the mouse or keyboard. But if I boot into the express gate the mouse and keyboard work fine...
I just made my switch from XP to vista 64bit. I also think I had XP for about 6.5 years. Loved every bit of it, but I can't deny that I'm enjoying vista.
No problems so far!!
Sorry about not stating the errors, here it is:
E:\Documents\SFSU\csci\arrayodd.cpp:30: error: `no' undeclared (first use this function)
E:\Documents\SFSU\csci\arrayodd.cpp:30: error: (Each undeclared identifier is reported only once for each function it appears in.)...
Here is the problem:
3. Write a function
void separator(int a[], int na, int odd[], int& no, int even[], int& ne)
that separates odd and even integers. For example, if a[]={1,2,3,4,5}, na=5, then odd[]={1,3,5},
no=3, even[]={2,4}, ne=2. Write a main program that illustrates the use of this...
And also for some reason when I try to compile it I am getting an error. The compiler is pointing to: sum += a[i];
Why could that be?
Edit:
So this is what I got:
#include <iostream.h>
using namespace std;
double sum (double a[], int n)
{
double i;
double sum...
void sum (double a[], int n)
{
double i;
double sum = 0;
for(i=n-1; i>=0; i--)
{
sum += a[i];
}
}
So when you say that I don't need i-- in the for loop.. what should I put there instead?
..By the way thanks for all your help. You...
Basically I can't even think of where to start. I think I'm not really getting the question.
1. Write a function
double sum(double a[ ], int n)
that returns the sum a[0]+a[1]+...+a[n-1]. Then write a main program that initializes an
array as follows:
y[0]=1/20 , y[1]=1/21 , y[2]=1/22 ...
I didn't mean to write it to make it look badass... it's just what I could think of at the time... after I came home is that I thought about if statements.
I hate the way the professor teaches, I have never heard of flowcharting...
Thanks for the input though
EDIT: By the way do you guys...
This morning I had my first programming midterm. The problem wanted me to write a program that asked for letter grades (a,b,c,d) and caculated the average GPA; A=4, B=3, C=2, and D=1
I pretty much remember everything I wrote down, I think I probably did some of it wrong though.
This is what I...
I have the following code:
#include <iostream>
void menu (void)
{
cout << "\n\n\nThe following options are available:\n"
<< "\n1. First Option"
<< "\n2. Second Option"
<< "\n3. Third Option"
<< "\n4. QUIT\n\nYour choice [1 - 4]: ";
}
int main(void)
{...
:D
wow... I did not know that if I wrote it with a capital letter it would not work.
Thanks a lot guys.
Wrote "for" instead of "For" and everything is good.
A simple for loop that is supposed to print out: 9876543
#include <iostream.h>
int main (void)
{
int x;
For (x=9; x>2; x--)
cout << x ;
return 0;
}
I keep getting two errors when compiling.
That is what I was thinking ^^
I'll try the else clause.
EDIT: I tried doing that and it still does not work. It just loops again when I enter a negative number.
EDIT2: I got it, i just needed to make it another if statement.
How can I incorporate swith statements instead of all these...
I want the program to terminate if I enter a negative number. Any help?
#include <iostream.h>
int main (void)
{
short int numgrade(0);
char lettergrade;
while (1) {
cout << "Enter a numeric grade (0 - 100): ";
cin >> numgrade...
It's not like I had not done the homework or anything like that.
The thing was pretty much done except for one little symbol was switched.
I could've went to my professor and he would've told me what was wrong with it.
It's not due until next wednesday, but I just like doing it ahead of...